x^2-8x+39=0

Solution for x^2-8x+39=0 equation:

Simplifying
x2 + -8x + 39 = 0

Reorder the terms:
39 + -8x + x2 = 0

Solving
39 + -8x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-39' to each side of the equation.
39 + -8x + -39 + x2 = 0 + -39

Reorder the terms:
39 + -39 + -8x + x2 = 0 + -39

Combine like terms: 39 + -39 = 0
0 + -8x + x2 = 0 + -39
-8x + x2 = 0 + -39

Combine like terms: 0 + -39 = -39
-8x + x2 = -39

The x term is -8x.  Take half its coefficient (-4).
Square it (16) and add it to both sides.

Add '16' to each side of the equation.
-8x + 16 + x2 = -39 + 16

Reorder the terms:
16 + -8x + x2 = -39 + 16

Combine like terms: -39 + 16 = -23
16 + -8x + x2 = -23

Factor a perfect square on the left side:
(x + -4)(x + -4) = -23

Can't calculate square root of the right side.

The solution to this equation could not be determined.